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FERMAT’S LAST THEOREM: THE COMPRHEHENSIVE PROOF
RESULTING IN CALCULATING ALGORITHM.
by Ivan M. Obushenko, Ph.D.
(Ukraine)
E-mail: obush@estart.com
The new approach for proving the legendary Fermat’s Last Theorem has been developed by making the proof light, brief, clear and enjoyable. One more advantage has been received from proposed consideration: the calculating algorithm for PC –
“ Obushenko-Fermat MachineÔ ” making the calculation process by fully automated and expendable unlimitedly. The “byproduct” of calculation is a finding of all integer triads fulfilling to the Pythagoras Theorem.
On February 25, 2005 I heard from the Ukrainian radio broadcast a presentation by Dr.Phys.-Math.Sci. on subject of the famous Fermat’s Last Theorem. She (well, what a difference, if it would be He?J) mentioned about enormous efforts made by Robert Wiles whose results were not recognized and accepted as the final proof (the same conclusion I met at reference [2]) that surprised me a lot because the acclaim made in the media about 10 or more years ago produced the impression of success on naïve public (well, on myself too). I remembered the theorem from my studies at the Senior High School (well, I had the really good teacher despite she lost to me a few “good” problems; so what? As a teacher she was very resourceful: I realized that when we’ve got a substitute man for the whole trimester…) when like anybody else I tried my “wings” on that prestigious subject too, which doesn’t seemed to be complicated on the first look and now – many years later – started again immediately on a fresh sight. Dr. Sci. summarized her lovely presentation by words about lying beyond the real world when you have deal with such thing as Fermat’s Theorem. Very scientifically and encouraging doesn’t it? It seemed to me I got some idea from air how to do it although it was not quite clear. Anyway I wrote some notes, which gave me impression that I am on right way and next day I told to my son that I did it. One more day later I’ve met the dead ends as before. But I already gave my word to my son and so I had nothing to do as go forward.
For integers a, b, c, and n>2 an + bn ¹ cn .
The current proof is substantially based on following Lemma expressing my basic idea led me forward.
Lemma. For any three numbers a, b, c, for which a + b > c some triangle can be constructed.
That Lemma arisen from the everyday experience and can’t be proved in principle on my opinion. So it rather Axiom than Lemma . Indeed, let’s make a drawing for a, b < c :
a m b
Drawing 1.
c
Case#1. What,
if a + b < c
Let’s put for clarity |a|<|b|<|c|, where |a|=mod a .
b’ Drawing. 2
a b
c